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20221001113003 = 184087710984439
BaseRepresentation
bin1001001100100000100011…
…00101101001110110101011
32122121002221100001021021021
410212100101211221312223
510122300102241104003
6111001222154553311
74154630154340405
oct446202145516653
978532840037237
1020221001113003
116496750a71279
122326b70438837
13b38aa85174a2
144dc9b7581b75
15250edbdc72bd
hex126411969dab

20221001113003 has 4 divisors (see below), whose sum is σ = 20221013938320. Its totient is φ = 20220988287688.

The previous prime is 20221001112971. The next prime is 20221001113037. The reversal of 20221001113003 is 30031110012202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20221001113003 - 25 = 20221001112971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20221001113043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3651343 + ... + 7333096.

It is an arithmetic number, because the mean of its divisors is an integer number (5055253484580).

Almost surely, 220221001113003 is an apocalyptic number.

20221001113003 is a deficient number, since it is larger than the sum of its proper divisors (12825317).

20221001113003 is a wasteful number, since it uses less digits than its factorization.

20221001113003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12825316.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 20221001113003 its reverse (30031110012202), we get a palindrome (50252111125205).

The spelling of 20221001113003 in words is "twenty trillion, two hundred twenty-one billion, one million, one hundred thirteen thousand, three".

Divisors: 1 1840877 10984439 20221001113003