Base | Representation |
---|---|
bin | 11101011011001110101… |
… | …011100010101101111011 |
3 | 21011022101202221101220122 |
4 | 131123032223202231323 |
5 | 231112231122300021 |
6 | 4144535122443455 |
7 | 266043401452136 |
oct | 35331653425573 |
9 | 7138352841818 |
10 | 2022102150011 |
11 | 70a628a47269 |
12 | 287a91b0358b |
13 | 1188b6600648 |
14 | 6dc2802121d |
15 | 378ed587bab |
hex | 1d6ceae2b7b |
2022102150011 has 2 divisors, whose sum is σ = 2022102150012. Its totient is φ = 2022102150010.
The previous prime is 2022102149989. The next prime is 2022102150041. The reversal of 2022102150011 is 1100512012202.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022102150011 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (2022102150041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011051075005 + 1011051075006.
It is an arithmetic number, because the mean of its divisors is an integer number (1011051075006).
Almost surely, 22022102150011 is an apocalyptic number.
2022102150011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022102150011 is an equidigital number, since it uses as much as digits as its factorization.
2022102150011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 2022102150011 its reverse (1100512012202), we get a palindrome (3122614162213).
The spelling of 2022102150011 in words is "two trillion, twenty-two billion, one hundred two million, one hundred fifty thousand, eleven".
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