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2022111002011 = 3754651648703
BaseRepresentation
bin11101011011001111001…
…101010011110110011011
321011022102101121010120111
4131123033031103312123
5231112240404031021
64144540040305151
7266043536630542
oct35331715236633
97138371533514
102022111002011
1170a632a42971
12287a94a721b7
131188b83ac809
146dc29287159
15378ee2358e1
hex1d6cf353d9b

2022111002011 has 4 divisors (see below), whose sum is σ = 2076762650752. Its totient is φ = 1967459353272.

The previous prime is 2022111001943. The next prime is 2022111002057. The reversal of 2022111002011 is 1102001112202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2022111002011 - 215 = 2022110969243 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2022111001982 and 2022111002000.

It is not an unprimeable number, because it can be changed into a prime (2022111402011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27325824315 + ... + 27325824388.

It is an arithmetic number, because the mean of its divisors is an integer number (519190662688).

Almost surely, 22022111002011 is an apocalyptic number.

2022111002011 is a deficient number, since it is larger than the sum of its proper divisors (54651648741).

2022111002011 is an equidigital number, since it uses as much as digits as its factorization.

2022111002011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54651648740.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2022111002011 its reverse (1102001112202), we get a palindrome (3124112114213).

The spelling of 2022111002011 in words is "two trillion, twenty-two billion, one hundred eleven million, two thousand, eleven".

Divisors: 1 37 54651648703 2022111002011