Base | Representation |
---|---|
bin | 11101011011001111001… |
… | …101110000111011101101 |
3 | 21011022102101211011222102 |
4 | 131123033031300323231 |
5 | 231112240421334013 |
6 | 4144540043024445 |
7 | 266043540635045 |
oct | 35331715607355 |
9 | 7138371734872 |
10 | 2022111121133 |
11 | 70a633014414 |
12 | 287a94b0b125 |
13 | 1188b8421abc |
14 | 6dc292b8725 |
15 | 378ee25ad58 |
hex | 1d6cf370eed |
2022111121133 has 2 divisors, whose sum is σ = 2022111121134. Its totient is φ = 2022111121132.
The previous prime is 2022111121111. The next prime is 2022111121181. The reversal of 2022111121133 is 3311211112202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1762131467209 + 259979653924 = 1327453^2 + 509882^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022111121133 - 214 = 2022111104749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2022111121633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011055560566 + 1011055560567.
It is an arithmetic number, because the mean of its divisors is an integer number (1011055560567).
Almost surely, 22022111121133 is an apocalyptic number.
It is an amenable number.
2022111121133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022111121133 is an equidigital number, since it uses as much as digits as its factorization.
2022111121133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2022111121133 its reverse (3311211112202), we get a palindrome (5333322233335).
The spelling of 2022111121133 in words is "two trillion, twenty-two billion, one hundred eleven million, one hundred twenty-one thousand, one hundred thirty-three".
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