Base | Representation |
---|---|
bin | 11101011011001111001… |
… | …101110011010111111011 |
3 | 21011022102101211200200201 |
4 | 131123033031303113323 |
5 | 231112240422144011 |
6 | 4144540043143031 |
7 | 266043541006150 |
oct | 35331715632773 |
9 | 7138371750621 |
10 | 2022111131131 |
11 | 70a633020983 |
12 | 287a94b14a77 |
13 | 1188b8426510 |
14 | 6dc292bc227 |
15 | 378ee25dcc1 |
hex | 1d6cf3735fb |
2022111131131 has 32 divisors (see below), whose sum is σ = 2579279754240. Its totient is φ = 1541917593216.
The previous prime is 2022111131101. The next prime is 2022111131147. The reversal of 2022111131131 is 1311311112202.
It is not a de Polignac number, because 2022111131131 - 25 = 2022111131099 is a prime.
It is a super-3 number, since 3×20221111311313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2022111131099 and 2022111131108.
It is not an unprimeable number, because it can be changed into a prime (2022111131101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 743130 + ... + 2143936.
It is an arithmetic number, because the mean of its divisors is an integer number (80602492320).
Almost surely, 22022111131131 is an apocalyptic number.
2022111131131 is a deficient number, since it is larger than the sum of its proper divisors (557168623109).
2022111131131 is a wasteful number, since it uses less digits than its factorization.
2022111131131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1401403.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 2022111131131 its reverse (1311311112202), we get a palindrome (3333422243333).
The spelling of 2022111131131 in words is "two trillion, twenty-two billion, one hundred eleven million, one hundred thirty-one thousand, one hundred thirty-one".
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