Base | Representation |
---|---|
bin | 11101011011001111110… |
… | …000000110001101111011 |
3 | 21011022110000202102202122 |
4 | 131123033300012031323 |
5 | 231112300222334321 |
6 | 4144541003551455 |
7 | 266044010301251 |
oct | 35331760061573 |
9 | 7138400672678 |
10 | 2022120121211 |
11 | 70a6381012a3 |
12 | 287a97b2b58b |
13 | 1188ba2534a8 |
14 | 6dc2a57c5d1 |
15 | 378eee378ab |
hex | 1d6cfc0637b |
2022120121211 has 2 divisors, whose sum is σ = 2022120121212. Its totient is φ = 2022120121210.
The previous prime is 2022120121201. The next prime is 2022120121223. The reversal of 2022120121211 is 1121210212202.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022120121211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2022120121211.
It is not a weakly prime, because it can be changed into another prime (2022120121201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011060060605 + 1011060060606.
It is an arithmetic number, because the mean of its divisors is an integer number (1011060060606).
Almost surely, 22022120121211 is an apocalyptic number.
2022120121211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022120121211 is an equidigital number, since it uses as much as digits as its factorization.
2022120121211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 2022120121211 its reverse (1121210212202), we get a palindrome (3143330333413).
Subtracting from 2022120121211 its reverse (1121210212202), we obtain a palindrome (900909909009).
The spelling of 2022120121211 in words is "two trillion, twenty-two billion, one hundred twenty million, one hundred twenty-one thousand, two hundred eleven".
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