Base | Representation |
---|---|
bin | 101101111110100100101101… |
… | …101001011110110111001011 |
3 | 222111222021211101202212211101 |
4 | 231332210231221132313023 |
5 | 203001020411001041021 |
6 | 1554022544354042231 |
7 | 60410225603445553 |
oct | 5576445551366713 |
9 | 874867741685741 |
10 | 202212121112011 |
11 | 5948175178817a |
12 | 1a81a092279377 |
13 | 88aa6a110003a |
14 | 37d11942dc163 |
15 | 185a0046d6a91 |
hex | b7e92da5edcb |
202212121112011 has 2 divisors, whose sum is σ = 202212121112012. Its totient is φ = 202212121112010.
The previous prime is 202212121111933. The next prime is 202212121112021. The reversal of 202212121112011 is 110211121212202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202212121112011 - 27 = 202212121111883 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 202212121112011.
It is not a weakly prime, because it can be changed into another prime (202212121112021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101106060556005 + 101106060556006.
It is an arithmetic number, because the mean of its divisors is an integer number (101106060556006).
Almost surely, 2202212121112011 is an apocalyptic number.
202212121112011 is a deficient number, since it is larger than the sum of its proper divisors (1).
202212121112011 is an equidigital number, since it uses as much as digits as its factorization.
202212121112011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 202212121112011 its reverse (110211121212202), we get a palindrome (312423242324213).
The spelling of 202212121112011 in words is "two hundred two trillion, two hundred twelve billion, one hundred twenty-one million, one hundred twelve thousand, eleven".
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