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2022131142041 is a prime number
BaseRepresentation
bin11101011011010000011…
…010001000110110011001
321011022110210111100111112
4131123100122020312121
5231112311033021131
64144542040110105
7266044203052043
oct35332032106631
97138423440445
102022131142041
1170a64334941a
12287a9b765335
131188bc6118aa
146dc2bc0aa93
1537900db302b
hex1d6d0688d99

2022131142041 has 2 divisors, whose sum is σ = 2022131142042. Its totient is φ = 2022131142040.

The previous prime is 2022131142029. The next prime is 2022131142089. The reversal of 2022131142041 is 1402411312202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1971609139600 + 50522002441 = 1404140^2 + 224771^2 .

It is a cyclic number.

It is not a de Polignac number, because 2022131142041 - 226 = 2022064033177 is a prime.

It is a super-2 number, since 2×20221311420412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2022131141998 and 2022131142016.

It is not a weakly prime, because it can be changed into another prime (2022131112041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011065571020 + 1011065571021.

It is an arithmetic number, because the mean of its divisors is an integer number (1011065571021).

Almost surely, 22022131142041 is an apocalyptic number.

It is an amenable number.

2022131142041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2022131142041 is an equidigital number, since it uses as much as digits as its factorization.

2022131142041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 2022131142041 its reverse (1402411312202), we get a palindrome (3424542454243).

The spelling of 2022131142041 in words is "two trillion, twenty-two billion, one hundred thirty-one million, one hundred forty-two thousand, forty-one".