Base | Representation |
---|---|
bin | 11101011011010000111… |
… | …100000101001111000011 |
3 | 21011022111102020102101102 |
4 | 131123100330011033003 |
5 | 231112320322241011 |
6 | 4144542554525015 |
7 | 266044341512021 |
oct | 35332074051703 |
9 | 7138442212342 |
10 | 2022140040131 |
11 | 70a648376712 |
12 | 287aa273676b |
13 | 1188c1408a33 |
14 | 6dc2d085711 |
15 | 37901a6e73b |
hex | 1d6d0f053c3 |
2022140040131 has 8 divisors (see below), whose sum is σ = 2067368358720. Its totient is φ = 1977003557568.
The previous prime is 2022140040127. The next prime is 2022140040149. The reversal of 2022140040131 is 1310400412202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2022140040131 - 22 = 2022140040127 is a prime.
It is a super-2 number, since 2×20221400401312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2022140040161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22914476 + ... + 23002553.
It is an arithmetic number, because the mean of its divisors is an integer number (258421044840).
Almost surely, 22022140040131 is an apocalyptic number.
2022140040131 is a deficient number, since it is larger than the sum of its proper divisors (45228318589).
2022140040131 is an equidigital number, since it uses as much as digits as its factorization.
2022140040131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45918013.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 2022140040131 its reverse (1310400412202), we get a palindrome (3332540452333).
The spelling of 2022140040131 in words is "two trillion, twenty-two billion, one hundred forty million, forty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •