Base | Representation |
---|---|
bin | 11101011011010000111… |
… | …100000101001111100001 |
3 | 21011022111102020102102112 |
4 | 131123100330011033201 |
5 | 231112320322241121 |
6 | 4144542554525105 |
7 | 266044341512063 |
oct | 35332074051741 |
9 | 7138442212375 |
10 | 2022140040161 |
11 | 70a64837673a |
12 | 287aa2736795 |
13 | 1188c1408a57 |
14 | 6dc2d085733 |
15 | 37901a6e75b |
hex | 1d6d0f053e1 |
2022140040161 has 2 divisors, whose sum is σ = 2022140040162. Its totient is φ = 2022140040160.
The previous prime is 2022140040149. The next prime is 2022140040197. The reversal of 2022140040161 is 1610400412202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2017195278400 + 4944761761 = 1420280^2 + 70319^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022140040161 - 218 = 2022139778017 is a prime.
It is not a weakly prime, because it can be changed into another prime (2022140000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011070020080 + 1011070020081.
It is an arithmetic number, because the mean of its divisors is an integer number (1011070020081).
Almost surely, 22022140040161 is an apocalyptic number.
It is an amenable number.
2022140040161 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022140040161 is an equidigital number, since it uses as much as digits as its factorization.
2022140040161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 2022140040161 its reverse (1610400412202), we get a palindrome (3632540452363).
The spelling of 2022140040161 in words is "two trillion, twenty-two billion, one hundred forty million, forty thousand, one hundred sixty-one".
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