Search a number
-
+
20222011000181 is a prime number
BaseRepresentation
bin1001001100100010011011…
…10010000100010101110101
32122121012112201022212001002
410212101031302010111311
510122304134304001211
6111001510312213045
74154664166261034
oct446211562042565
978535481285032
1020222011000181
11649711a028481
1223271b269a185
13b38c09806a73
144dca7174471b
1525104a8ad03b
hex12644dc84575

20222011000181 has 2 divisors, whose sum is σ = 20222011000182. Its totient is φ = 20222011000180.

The previous prime is 20222011000157. The next prime is 20222011000207. The reversal of 20222011000181 is 18100011022202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16467290956081 + 3754720044100 = 4057991^2 + 1937710^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20222011000181 is a prime.

It is a super-2 number, since 2×202220110001812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20222011009181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10111005500090 + 10111005500091.

It is an arithmetic number, because the mean of its divisors is an integer number (10111005500091).

Almost surely, 220222011000181 is an apocalyptic number.

It is an amenable number.

20222011000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

20222011000181 is an equidigital number, since it uses as much as digits as its factorization.

20222011000181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 20222011000181 its reverse (18100011022202), we get a palindrome (38322022022383).

The spelling of 20222011000181 in words is "twenty trillion, two hundred twenty-two billion, eleven million, one hundred eighty-one", and thus it is an aban number.