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2022202011113 is a prime number
BaseRepresentation
bin11101011011010100101…
…000011110110111101001
321011022122201211212120222
4131123110220132313221
5231112432203323423
64144553051055425
7266046023325314
oct35332450366751
97138581755528
102022202011113
1170a67a3533a9
12287abb441575
131189011c5b5b
146dc373b797b
15379072113c8
hex1d6d4a1ede9

2022202011113 has 2 divisors, whose sum is σ = 2022202011114. Its totient is φ = 2022202011112.

The previous prime is 2022202011103. The next prime is 2022202011127. The reversal of 2022202011113 is 3111102022202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1021257788329 + 1000944222784 = 1010573^2 + 1000472^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2022202011113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2022202011091 and 2022202011100.

It is not a weakly prime, because it can be changed into another prime (2022202011103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011101005556 + 1011101005557.

It is an arithmetic number, because the mean of its divisors is an integer number (1011101005557).

Almost surely, 22022202011113 is an apocalyptic number.

It is an amenable number.

2022202011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2022202011113 is an equidigital number, since it uses as much as digits as its factorization.

2022202011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 2022202011113 its reverse (3111102022202), we get a palindrome (5133304033315).

The spelling of 2022202011113 in words is "two trillion, twenty-two billion, two hundred two million, eleven thousand, one hundred thirteen".