Base | Representation |
---|---|
bin | 11101011011010100101… |
… | …000011110110111101001 |
3 | 21011022122201211212120222 |
4 | 131123110220132313221 |
5 | 231112432203323423 |
6 | 4144553051055425 |
7 | 266046023325314 |
oct | 35332450366751 |
9 | 7138581755528 |
10 | 2022202011113 |
11 | 70a67a3533a9 |
12 | 287abb441575 |
13 | 1189011c5b5b |
14 | 6dc373b797b |
15 | 379072113c8 |
hex | 1d6d4a1ede9 |
2022202011113 has 2 divisors, whose sum is σ = 2022202011114. Its totient is φ = 2022202011112.
The previous prime is 2022202011103. The next prime is 2022202011127. The reversal of 2022202011113 is 3111102022202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1021257788329 + 1000944222784 = 1010573^2 + 1000472^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022202011113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2022202011091 and 2022202011100.
It is not a weakly prime, because it can be changed into another prime (2022202011103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011101005556 + 1011101005557.
It is an arithmetic number, because the mean of its divisors is an integer number (1011101005557).
Almost surely, 22022202011113 is an apocalyptic number.
It is an amenable number.
2022202011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022202011113 is an equidigital number, since it uses as much as digits as its factorization.
2022202011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2022202011113 its reverse (3111102022202), we get a palindrome (5133304033315).
The spelling of 2022202011113 in words is "two trillion, twenty-two billion, two hundred two million, eleven thousand, one hundred thirteen".
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