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20222020433 is a prime number
BaseRepresentation
bin10010110101010100…
…111000101101010001
31221012022022002000202
4102311110320231101
5312403314123213
613142340024545
71314056223536
oct226524705521
957168262022
1020222020433
11863789228a
123b04392155
131ba36a1b84
14d9b99ad8d
157d54c4b58
hex4b5538b51

20222020433 has 2 divisors, whose sum is σ = 20222020434. Its totient is φ = 20222020432.

The previous prime is 20222020411. The next prime is 20222020439. The reversal of 20222020433 is 33402022202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19935463249 + 286557184 = 141193^2 + 16928^2 .

It is a cyclic number.

It is not a de Polignac number, because 20222020433 - 220 = 20220971857 is a prime.

It is a super-2 number, since 2×202220204332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20222020439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10111010216 + 10111010217.

It is an arithmetic number, because the mean of its divisors is an integer number (10111010217).

Almost surely, 220222020433 is an apocalyptic number.

It is an amenable number.

20222020433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20222020433 is an equidigital number, since it uses as much as digits as its factorization.

20222020433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 20.

Adding to 20222020433 its reverse (33402022202), we get a palindrome (53624042635).

The spelling of 20222020433 in words is "twenty billion, two hundred twenty-two million, twenty thousand, four hundred thirty-three".