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202222002021253 is a prime number
BaseRepresentation
bin101101111110101101111010…
…100110001010001110000101
3222112000020100000110002010221
4231332231322212022032011
5203001201130004140003
61554031301044144341
760411025504004254
oct5576557246121605
9875006300402127
10202222002021253
1159485962251575
121a81bb8b3980b1
1388ab5b72213b6
1437d185070079b
15185a3d1dbd7bd
hexb7eb7a98a385

202222002021253 has 2 divisors, whose sum is σ = 202222002021254. Its totient is φ = 202222002021252.

The previous prime is 202222002021203. The next prime is 202222002021283. The reversal of 202222002021253 is 352120200222202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199401002967364 + 2820999053889 = 14120942^2 + 1679583^2 .

It is a cyclic number.

It is not a de Polignac number, because 202222002021253 - 221 = 202221999924101 is a prime.

It is a super-4 number, since 4×2022220020212534 (a number of 58 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202222002021203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101111001010626 + 101111001010627.

It is an arithmetic number, because the mean of its divisors is an integer number (101111001010627).

Almost surely, 2202222002021253 is an apocalyptic number.

It is an amenable number.

202222002021253 is a deficient number, since it is larger than the sum of its proper divisors (1).

202222002021253 is an equidigital number, since it uses as much as digits as its factorization.

202222002021253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 25.

Adding to 202222002021253 its reverse (352120200222202), we get a palindrome (554342202243455).

The spelling of 202222002021253 in words is "two hundred two trillion, two hundred twenty-two billion, two million, twenty-one thousand, two hundred fifty-three".