Base | Representation |
---|---|
bin | 11101011011011011111… |
… | …011000110101001001011 |
3 | 21011022222021000110212002 |
4 | 131123123323012221023 |
5 | 231113210012130011 |
6 | 4145013140541215 |
7 | 266052040130264 |
oct | 35333373065113 |
9 | 7138867013762 |
10 | 2022324333131 |
11 | 70a732400783 |
12 | 287b343b180b |
13 | 11892065394b |
14 | 6dc4973996b |
15 | 37912d24c3b |
hex | 1d6dbec6a4b |
2022324333131 has 2 divisors, whose sum is σ = 2022324333132. Its totient is φ = 2022324333130.
The previous prime is 2022324332989. The next prime is 2022324333251. The reversal of 2022324333131 is 1313334232202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022324333131 is a prime.
It is a super-2 number, since 2×20223243331312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 2022324333094 and 2022324333103.
It is not a weakly prime, because it can be changed into another prime (2022324332131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011162166565 + 1011162166566.
It is an arithmetic number, because the mean of its divisors is an integer number (1011162166566).
Almost surely, 22022324333131 is an apocalyptic number.
2022324333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022324333131 is an equidigital number, since it uses as much as digits as its factorization.
2022324333131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 2022324333131 its reverse (1313334232202), we get a palindrome (3335658565333).
The spelling of 2022324333131 in words is "two trillion, twenty-two billion, three hundred twenty-four million, three hundred thirty-three thousand, one hundred thirty-one".
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