Search a number
-
+
20224001340433 = 111838545576403
BaseRepresentation
bin1001001100100110001000…
…11010100111010000010001
32122121101200102111121120201
410212103010122213100101
510122322223320343213
6111002440012135201
74155064415011222
oct446230432472021
978541612447521
1020224001340433
116497a50577580
122327669167501
13b39165c7b3a7
144dcbbdc07249
152511154b36dd
hex1264c46a7411

20224001340433 has 4 divisors (see below), whose sum is σ = 22062546916848. Its totient is φ = 18385455764020.

The previous prime is 20224001340397. The next prime is 20224001340437. The reversal of 20224001340433 is 33404310042202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20224001340433 - 229 = 20223464469521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20224001340437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 919272788191 + ... + 919272788212.

It is an arithmetic number, because the mean of its divisors is an integer number (5515636729212).

Almost surely, 220224001340433 is an apocalyptic number.

It is an amenable number.

20224001340433 is a deficient number, since it is larger than the sum of its proper divisors (1838545576415).

20224001340433 is a wasteful number, since it uses less digits than its factorization.

20224001340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1838545576414.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 20224001340433 its reverse (33404310042202), we get a palindrome (53628311382635).

The spelling of 20224001340433 in words is "twenty trillion, two hundred twenty-four billion, one million, three hundred forty thousand, four hundred thirty-three".

Divisors: 1 11 1838545576403 20224001340433