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20230343411 = 84121240491
BaseRepresentation
bin10010110101110100…
…101000101011110011
31221012212221221000012
4102311310220223303
5312412431442121
613143234245135
71314220040015
oct226564505363
957185857005
1020230343411
118641557483
123b071267ab
131ba5327305
14d9cb261b5
157d60bac5b
hex4b5d28af3

20230343411 has 4 divisors (see below), whose sum is σ = 20230668024. Its totient is φ = 20230018800.

The previous prime is 20230343401. The next prime is 20230343437. The reversal of 20230343411 is 11434303202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20230343411 - 214 = 20230327027 is a prime.

It is a super-2 number, since 2×202303434112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20230343401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36125 + ... + 204366.

It is an arithmetic number, because the mean of its divisors is an integer number (5057667006).

Almost surely, 220230343411 is an apocalyptic number.

20230343411 is a deficient number, since it is larger than the sum of its proper divisors (324613).

20230343411 is an equidigital number, since it uses as much as digits as its factorization.

20230343411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 324612.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 20230343411 its reverse (11434303202), we get a palindrome (31664646613).

The spelling of 20230343411 in words is "twenty billion, two hundred thirty million, three hundred forty-three thousand, four hundred eleven".

Divisors: 1 84121 240491 20230343411