20230425254035 has 4 divisors (see below), whose sum is σ = 24276510304848. Its totient is φ = 16184340203224.

The previous prime is 20230425254027. The next prime is 20230425254059. The reversal of 20230425254035 is 53045252403202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20230425254035 - 2³ = 20230425254027 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20230425253985 and 20230425254003.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2023042525399 + ... + 2023042525408.

It is an arithmetic number, because the mean of its divisors is an integer number (6069127576212).

Almost surely, 2^{20230425254035} is an apocalyptic number.

20230425254035 is a deficient number, since it is larger than the sum of its proper divisors (4046085050813).

20230425254035 is an equidigital number, since it uses as much as digits as its factorization.

20230425254035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4046085050812.

The product of its (nonzero) digits is 288000, while the sum is 37.

Adding to 20230425254035 its reverse (53045252403202), we get a palindrome (73275677657237).

The spelling of 20230425254035 in words is "twenty trillion, two hundred thirty billion, four hundred twenty-five million, two hundred fifty-four thousand, thirty-five".