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20231110113 = 36743703371
BaseRepresentation
bin10010110101110111…
…100011110111100001
31221012221101212201120
4102311313203313201
5312413131010423
613143302522453
71314226412214
oct226567436741
957187355646
1020231110113
118641a30515
123b07436429
131ba5535296
14d9cc8577b
157d61bcee3
hex4b5de3de1

20231110113 has 4 divisors (see below), whose sum is σ = 26974813488. Its totient is φ = 13487406740.

The previous prime is 20231110103. The next prime is 20231110139. The reversal of 20231110113 is 31101113202.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20231110113 - 210 = 20231109089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20231110092 and 20231110101.

It is not an unprimeable number, because it can be changed into a prime (20231110103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3371851683 + ... + 3371851688.

It is an arithmetic number, because the mean of its divisors is an integer number (6743703372).

Almost surely, 220231110113 is an apocalyptic number.

It is an amenable number.

20231110113 is a deficient number, since it is larger than the sum of its proper divisors (6743703375).

20231110113 is an equidigital number, since it uses as much as digits as its factorization.

20231110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6743703374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 20231110113 its reverse (31101113202), we get a palindrome (51332223315).

The spelling of 20231110113 in words is "twenty billion, two hundred thirty-one million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 3 6743703371 20231110113