Base | Representation |
---|---|
bin | 11101011100001010111… |
… | …101001101001101000011 |
3 | 21011102000020210220112211 |
4 | 131130022331031031003 |
5 | 231121314013212233 |
6 | 4145223325402551 |
7 | 266110431164053 |
oct | 35341275151503 |
9 | 7142006726484 |
10 | 2023113413443 |
11 | 70aaa7863471 |
12 | 288114709457 |
13 | 118a17c82485 |
14 | 6dcc2461563 |
15 | 3795c2415cd |
hex | 1d70af4d343 |
2023113413443 has 16 divisors (see below), whose sum is σ = 2201700242880. Its totient is φ = 1851848064000.
The previous prime is 2023113413437. The next prime is 2023113413491. The reversal of 2023113413443 is 3443143113202.
It is a cyclic number.
It is not a de Polignac number, because 2023113413443 - 217 = 2023113282371 is a prime.
It is a super-2 number, since 2×20231134134432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2023113413543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10867983 + ... + 11052568.
It is an arithmetic number, because the mean of its divisors is an integer number (137606265180).
Almost surely, 22023113413443 is an apocalyptic number.
2023113413443 is a deficient number, since it is larger than the sum of its proper divisors (178586829437).
2023113413443 is a wasteful number, since it uses less digits than its factorization.
2023113413443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21920718.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 2023113413443 its reverse (3443143113202), we get a palindrome (5466256526645).
The spelling of 2023113413443 in words is "two trillion, twenty-three billion, one hundred thirteen million, four hundred thirteen thousand, four hundred forty-three".
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