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2023113413443 = 17618921920551
BaseRepresentation
bin11101011100001010111…
…101001101001101000011
321011102000020210220112211
4131130022331031031003
5231121314013212233
64145223325402551
7266110431164053
oct35341275151503
97142006726484
102023113413443
1170aaa7863471
12288114709457
13118a17c82485
146dcc2461563
153795c2415cd
hex1d70af4d343

2023113413443 has 16 divisors (see below), whose sum is σ = 2201700242880. Its totient is φ = 1851848064000.

The previous prime is 2023113413437. The next prime is 2023113413491. The reversal of 2023113413443 is 3443143113202.

It is a cyclic number.

It is not a de Polignac number, because 2023113413443 - 217 = 2023113282371 is a prime.

It is a super-2 number, since 2×20231134134432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2023113413543) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10867983 + ... + 11052568.

It is an arithmetic number, because the mean of its divisors is an integer number (137606265180).

Almost surely, 22023113413443 is an apocalyptic number.

2023113413443 is a deficient number, since it is larger than the sum of its proper divisors (178586829437).

2023113413443 is a wasteful number, since it uses less digits than its factorization.

2023113413443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21920718.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 2023113413443 its reverse (3443143113202), we get a palindrome (5466256526645).

The spelling of 2023113413443 in words is "two trillion, twenty-three billion, one hundred thirteen million, four hundred thirteen thousand, four hundred forty-three".

Divisors: 1 17 61 89 1037 1513 5429 92293 21920551 372649367 1337153611 1950929039 22731611387 33165793663 119006671379 2023113413443