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20231223305155 = 57915951115409
BaseRepresentation
bin1001001100110011100101…
…11000001110001111000011
32122122002022201220102201121
410212121302320032033003
510122432021131231110
6111010032400013111
74155441400466032
oct446316270161703
978562281812647
1020231223305155
1164a0017146565
122328b43901197
13b39a4725c0b5
144dd2a7022719
152513d9524cda
hex126672e0e3c3

20231223305155 has 8 divisors (see below), whose sum is σ = 24277775133600. Its totient is φ = 16184773865856.

The previous prime is 20231223305147. The next prime is 20231223305213. The reversal of 20231223305155 is 55150332213202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20231223305155 - 23 = 20231223305147 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20231223305155.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25161910 + ... + 25953499.

It is an arithmetic number, because the mean of its divisors is an integer number (3034721891700).

Almost surely, 220231223305155 is an apocalyptic number.

20231223305155 is a deficient number, since it is larger than the sum of its proper divisors (4046551828445).

20231223305155 is an equidigital number, since it uses as much as digits as its factorization.

20231223305155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51194573.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 20231223305155 its reverse (55150332213202), we get a palindrome (75381555518357).

The spelling of 20231223305155 in words is "twenty trillion, two hundred thirty-one billion, two hundred twenty-three million, three hundred five thousand, one hundred fifty-five".

Divisors: 1 5 79159 395795 51115409 255577045 4046244661031 20231223305155