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2023143000111 = 32224793666679
BaseRepresentation
bin11101011100001100101…
…110000100100000101111
321011102002022111001211100
4131130030232010200233
5231121344102000421
64145230303454143
7266111240521422
oct35341456044057
97142068431740
102023143000111
11710012531362
122881225b7353
13118a2114128c
146dcc63639b9
153795eb37c26
hex1d70cb8482f

2023143000111 has 6 divisors (see below), whose sum is σ = 2922317666840. Its totient is φ = 1348762000068.

The previous prime is 2023143000071. The next prime is 2023143000169. The reversal of 2023143000111 is 1110003413202.

2023143000111 is a `hidden beast` number, since 2 + 0 + 231 + 430 + 0 + 0 + 1 + 1 + 1 = 666.

It is not a de Polignac number, because 2023143000111 - 223 = 2023134611503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2023143000181) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 112396833331 + ... + 112396833348.

Almost surely, 22023143000111 is an apocalyptic number.

2023143000111 is a deficient number, since it is larger than the sum of its proper divisors (899174666729).

2023143000111 is a wasteful number, since it uses less digits than its factorization.

2023143000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224793666685 (or 224793666682 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 2023143000111 its reverse (1110003413202), we get a palindrome (3133146413313).

The spelling of 2023143000111 in words is "two trillion, twenty-three billion, one hundred forty-three million, one hundred eleven", and thus it is an aban number.

Divisors: 1 3 9 224793666679 674381000037 2023143000111