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202324323104419 is a prime number
BaseRepresentation
bin101110000000001101001101…
…011010000111011010100011
3222112101000102221121122220211
4232000031031122013122203
5203004340203203320134
61554150302204114551
760421310223604135
oct5600151532073243
9875330387548824
10202324323104419
115951529989881a
121a837986535a57
1388b8142878419
1437d6799b1b055
15185cdbec91764
hexb8034d6876a3

202324323104419 has 2 divisors, whose sum is σ = 202324323104420. Its totient is φ = 202324323104418.

The previous prime is 202324323104389. The next prime is 202324323104459. The reversal of 202324323104419 is 914401323423202.

It is an a-pointer prime, because the next prime (202324323104459) can be obtained adding 202324323104419 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 202324323104419 - 29 = 202324323103907 is a prime.

It is a super-3 number, since 3×2023243231044193 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (202324323104459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101162161552209 + 101162161552210.

It is an arithmetic number, because the mean of its divisors is an integer number (101162161552210).

Almost surely, 2202324323104419 is an apocalyptic number.

202324323104419 is a deficient number, since it is larger than the sum of its proper divisors (1).

202324323104419 is an equidigital number, since it uses as much as digits as its factorization.

202324323104419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 202324323104419 in words is "two hundred two trillion, three hundred twenty-four billion, three hundred twenty-three million, one hundred four thousand, four hundred nineteen".