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2023251143313 = 3674417047771
BaseRepresentation
bin11101011100010011001…
…010100110101010010001
321011102100211222022102010
4131130103022212222101
5231122104243041223
64145245125413133
7266114022650631
oct35342312465221
97142324868363
102023251143313
11710068584a04
1228815286a1a9
13118a3a67643a
146dcd68746c1
153796939a393
hex1d7132a6a91

2023251143313 has 4 divisors (see below), whose sum is σ = 2697668191088. Its totient is φ = 1348834095540.

The previous prime is 2023251143233. The next prime is 2023251143341. The reversal of 2023251143313 is 3133411523202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2023251143313 - 225 = 2023217588881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2023251143413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337208523883 + ... + 337208523888.

It is an arithmetic number, because the mean of its divisors is an integer number (674417047772).

Almost surely, 22023251143313 is an apocalyptic number.

It is an amenable number.

2023251143313 is a deficient number, since it is larger than the sum of its proper divisors (674417047775).

2023251143313 is an equidigital number, since it uses as much as digits as its factorization.

2023251143313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 674417047774.

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 2023251143313 its reverse (3133411523202), we get a palindrome (5156662666515).

The spelling of 2023251143313 in words is "two trillion, twenty-three billion, two hundred fifty-one million, one hundred forty-three thousand, three hundred thirteen".

Divisors: 1 3 674417047771 2023251143313