Base | Representation |
---|---|
bin | 1001001100110110111101… |
… | …01111101100101110000011 |
3 | 2122122020222212011222010212 |
4 | 10212123132233230232003 |
5 | 10122444222422310201 |
6 | 111010532124144335 |
7 | 4155534263643431 |
oct | 446333657545603 |
9 | 78566885158125 |
10 | 20233033010051 |
11 | 64a0865729644 |
12 | 23293699980ab |
13 | b39c751695b4 |
14 | 4dd3d9503d51 |
15 | 251493348abb |
hex | 1266debecb83 |
20233033010051 has 2 divisors, whose sum is σ = 20233033010052. Its totient is φ = 20233033010050.
The previous prime is 20233033010011. The next prime is 20233033010059. The reversal of 20233033010051 is 15001033033202.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20233033010051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20233033009999 and 20233033010026.
It is not a weakly prime, because it can be changed into another prime (20233033010059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10116516505025 + 10116516505026.
It is an arithmetic number, because the mean of its divisors is an integer number (10116516505026).
Almost surely, 220233033010051 is an apocalyptic number.
20233033010051 is a deficient number, since it is larger than the sum of its proper divisors (1).
20233033010051 is an equidigital number, since it uses as much as digits as its factorization.
20233033010051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 23.
Adding to 20233033010051 its reverse (15001033033202), we get a palindrome (35234066043253).
The spelling of 20233033010051 in words is "twenty trillion, two hundred thirty-three billion, thirty-three million, ten thousand, fifty-one".
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