Base | Representation |
---|---|
bin | 11101011100011100010… |
… | …010001000100100001111 |
3 | 21011102202111210221012100 |
4 | 131130130102020210033 |
5 | 231122412423042033 |
6 | 4145312232210143 |
7 | 266120561114121 |
oct | 35343422104417 |
9 | 7142674727170 |
10 | 2023404112143 |
11 | 710136964727 |
12 | 288195b39953 |
13 | 118a6327473b |
14 | 6dd0ccd3211 |
15 | 37977a14513 |
hex | 1d71c48890f |
2023404112143 has 12 divisors (see below), whose sum is σ = 2935801086400. Its totient is φ = 1342887032736.
The previous prime is 2023404112141. The next prime is 2023404112193. The reversal of 2023404112143 is 3412114043202.
2023404112143 is a `hidden beast` number, since 2 + 0 + 2 + 3 + 404 + 112 + 143 = 666.
It is not a de Polignac number, because 2023404112143 - 21 = 2023404112141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2023404112141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 504084718 + ... + 504088731.
Almost surely, 22023404112143 is an apocalyptic number.
2023404112143 is a deficient number, since it is larger than the sum of its proper divisors (912396974257).
2023404112143 is a wasteful number, since it uses less digits than its factorization.
2023404112143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1008173678 (or 1008173675 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 2023404112143 its reverse (3412114043202), we get a palindrome (5435518155345).
The spelling of 2023404112143 in words is "two trillion, twenty-three billion, four hundred four million, one hundred twelve thousand, one hundred forty-three".
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