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2023434442241 is a prime number
BaseRepresentation
bin11101011100011110000…
…101110101011000000001
321011102211121212212021022
4131130132011311120001
5231122443204122431
64145315234235225
7266121406656062
oct35343605653001
97142747785238
102023434442241
11710151aa0123
122881a4125b15
13118a69633a44
146dd12d4a569
153797a50607b
hex1d71e175601

2023434442241 has 2 divisors, whose sum is σ = 2023434442242. Its totient is φ = 2023434442240.

The previous prime is 2023434442219. The next prime is 2023434442243. The reversal of 2023434442241 is 1422444343202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1614243939841 + 409190502400 = 1270529^2 + 639680^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2023434442241 is a prime.

It is a super-3 number, since 3×20234344422413 (a number of 38 digits) contains 333 as substring.

Together with 2023434442243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2023434442243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011717221120 + 1011717221121.

It is an arithmetic number, because the mean of its divisors is an integer number (1011717221121).

Almost surely, 22023434442241 is an apocalyptic number.

It is an amenable number.

2023434442241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023434442241 is an equidigital number, since it uses as much as digits as its factorization.

2023434442241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 147456, while the sum is 35.

Adding to 2023434442241 its reverse (1422444343202), we get a palindrome (3445878785443).

The spelling of 2023434442241 in words is "two trillion, twenty-three billion, four hundred thirty-four million, four hundred forty-two thousand, two hundred forty-one".