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2023502121437 is a prime number
BaseRepresentation
bin11101011100100010001…
…000000000100111011101
321011110000100020022200012
4131130202020000213131
5231123113020341222
64145330053013005
7266123161145366
oct35344210004735
97143010208605
102023502121437
11710187216545
12288202924165
13118a7a66c0c4
146dd1bd26b6d
15379814241e2
hex1d7222009dd

2023502121437 has 2 divisors, whose sum is σ = 2023502121438. Its totient is φ = 2023502121436.

The previous prime is 2023502121427. The next prime is 2023502121491. The reversal of 2023502121437 is 7341212053202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1297033987876 + 726468133561 = 1138874^2 + 852331^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023502121437 - 218 = 2023501859293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023502121427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011751060718 + 1011751060719.

It is an arithmetic number, because the mean of its divisors is an integer number (1011751060719).

Almost surely, 22023502121437 is an apocalyptic number.

It is an amenable number.

2023502121437 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023502121437 is an equidigital number, since it uses as much as digits as its factorization.

2023502121437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 32.

Adding to 2023502121437 its reverse (7341212053202), we get a palindrome (9364714174639).

The spelling of 2023502121437 in words is "two trillion, twenty-three billion, five hundred two million, one hundred twenty-one thousand, four hundred thirty-seven".