Base | Representation |
---|---|
bin | 1001001100111111101001… |
… | …11011110001011110110111 |
3 | 2122122201001010101212211210 |
4 | 10212133310323301132313 |
5 | 10123033302230210320 |
6 | 111013023211132503 |
7 | 4156061035521633 |
oct | 446376473613667 |
9 | 78581033355753 |
10 | 20237700241335 |
11 | 64a2840210585 |
12 | 232a250a44133 |
13 | b3a53a096105 |
14 | 4dd71d301dc3 |
15 | 251667e6c0e0 |
hex | 1267f4ef17b7 |
20237700241335 has 32 divisors (see below), whose sum is σ = 34329760416000. Its totient is φ = 10151800540416.
The previous prime is 20237700241321. The next prime is 20237700241379. The reversal of 20237700241335 is 53314200773202.
It is not a de Polignac number, because 20237700241335 - 217 = 20237700110263 is a prime.
It is a super-2 number, since 2×202377002413352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20237700241293 and 20237700241302.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 255390150 + ... + 255469379.
It is an arithmetic number, because the mean of its divisors is an integer number (1072805013000).
Almost surely, 220237700241335 is an apocalyptic number.
20237700241335 is a deficient number, since it is larger than the sum of its proper divisors (14092060174665).
20237700241335 is a wasteful number, since it uses less digits than its factorization.
20237700241335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 510859695.
The product of its (nonzero) digits is 211680, while the sum is 39.
The spelling of 20237700241335 in words is "twenty trillion, two hundred thirty-seven billion, seven hundred million, two hundred forty-one thousand, three hundred thirty-five".
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