Base | Representation |
---|---|
bin | 1001001101000100001100… |
… | …11111000110110110111011 |
3 | 2122122221100022101020201121 |
4 | 10212202012133012312323 |
5 | 10123103302400402001 |
6 | 111014105402530111 |
7 | 4156205410032451 |
oct | 446420637066673 |
9 | 78587308336647 |
10 | 20240142200251 |
11 | 64a3883681446 |
12 | 232a812806937 |
13 | b3a838c8310c |
14 | 4dd8b17649d1 |
15 | 25175c5306a1 |
hex | 1268867c6dbb |
20240142200251 has 2 divisors, whose sum is σ = 20240142200252. Its totient is φ = 20240142200250.
The previous prime is 20240142200209. The next prime is 20240142200279. The reversal of 20240142200251 is 15200224104202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20240142200251 - 211 = 20240142198203 is a prime.
It is not a weakly prime, because it can be changed into another prime (20240142200351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10120071100125 + 10120071100126.
It is an arithmetic number, because the mean of its divisors is an integer number (10120071100126).
Almost surely, 220240142200251 is an apocalyptic number.
20240142200251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20240142200251 is an equidigital number, since it uses as much as digits as its factorization.
20240142200251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 20240142200251 its reverse (15200224104202), we get a palindrome (35440366304453).
The spelling of 20240142200251 in words is "twenty trillion, two hundred forty billion, one hundred forty-two million, two hundred thousand, two hundred fifty-one".
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