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20241324113 is a prime number
BaseRepresentation
bin10010110110011110…
…100001100001010001
31221020122121210200212
4102312132201201101
5312423234332423
613144305453505
71314412262513
oct226636414121
957218553625
1020241324113
11864777743a
123b0a941295
131ba76a037a
14da0383bb3
157d7039578
hex4b67a1851

20241324113 has 2 divisors, whose sum is σ = 20241324114. Its totient is φ = 20241324112.

The previous prime is 20241324083. The next prime is 20241324121. The reversal of 20241324113 is 31142314202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20116599889 + 124724224 = 141833^2 + 11168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20241324113 is a prime.

It is a super-2 number, since 2×202413241132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20241314113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10120662056 + 10120662057.

It is an arithmetic number, because the mean of its divisors is an integer number (10120662057).

Almost surely, 220241324113 is an apocalyptic number.

It is an amenable number.

20241324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20241324113 is an equidigital number, since it uses as much as digits as its factorization.

20241324113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 20241324113 its reverse (31142314202), we get a palindrome (51383638315).

The spelling of 20241324113 in words is "twenty billion, two hundred forty-one million, three hundred twenty-four thousand, one hundred thirteen".