Base | Representation |
---|---|
bin | 1001001101011000101010… |
… | …01100101101100101011111 |
3 | 2122200222200211012012000121 |
4 | 10212230111030231211133 |
5 | 10123243301333021443 |
6 | 111023123345335411 |
7 | 4160044535455621 |
oct | 446542514554537 |
9 | 78628624165017 |
10 | 20251126454623 |
11 | 64a84aaa35319 |
12 | 2330979337567 |
13 | b3b89985690c |
14 | 5002344d6c11 |
15 | 251ba1a0e4ed |
hex | 126b1532d95f |
20251126454623 has 2 divisors, whose sum is σ = 20251126454624. Its totient is φ = 20251126454622.
The previous prime is 20251126454617. The next prime is 20251126454639. The reversal of 20251126454623 is 32645462115202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20251126454623 - 217 = 20251126323551 is a prime.
It is a super-2 number, since 2×202511264546232 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20251126454623.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20251126451623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125563227311 + 10125563227312.
It is an arithmetic number, because the mean of its divisors is an integer number (10125563227312).
Almost surely, 220251126454623 is an apocalyptic number.
20251126454623 is a deficient number, since it is larger than the sum of its proper divisors (1).
20251126454623 is an equidigital number, since it uses as much as digits as its factorization.
20251126454623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 43.
Adding to 20251126454623 its reverse (32645462115202), we get a palindrome (52896588569825).
The spelling of 20251126454623 in words is "twenty trillion, two hundred fifty-one billion, one hundred twenty-six million, four hundred fifty-four thousand, six hundred twenty-three".
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