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202512397 is a prime number
BaseRepresentation
bin11000001001000…
…01100000001101
3112010001200210011
430010201200031
5403320344042
632032313221
75006220103
oct1404414015
9463050704
10202512397
11a434961a
12579a2811
1332c56a29
141cc77c73
1512ba3a17
hexc12180d

202512397 has 2 divisors, whose sum is σ = 202512398. Its totient is φ = 202512396.

The previous prime is 202512361. The next prime is 202512403. The reversal of 202512397 is 793215202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130279396 + 72233001 = 11414^2 + 8499^2 .

It is a cyclic number.

It is not a de Polignac number, because 202512397 - 27 = 202512269 is a prime.

It is a super-2 number, since 2×2025123972 = 82022541877371218, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202512797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101256198 + 101256199.

It is an arithmetic number, because the mean of its divisors is an integer number (101256199).

Almost surely, 2202512397 is an apocalyptic number.

It is an amenable number.

202512397 is a deficient number, since it is larger than the sum of its proper divisors (1).

202512397 is an equidigital number, since it uses as much as digits as its factorization.

202512397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 31.

The square root of 202512397 is about 14230.6850502708. The cubic root of 202512397 is about 587.2421292923.

Adding to 202512397 its reverse (793215202), we get a palindrome (995727599).

The spelling of 202512397 in words is "two hundred two million, five hundred twelve thousand, three hundred ninety-seven".