Search a number
-
+
2025132051 = 3675044017
BaseRepresentation
bin111100010110101…
…0001000000010011
312020010122100220210
41320231101000103
513121413211201
6532541335203
7101120224035
oct17055210023
95203570823
102025132051
1194a152758
12486267503
132637366b7
14152d5bc55
15bcbc91d6
hex78b51013

2025132051 has 4 divisors (see below), whose sum is σ = 2700176072. Its totient is φ = 1350088032.

The previous prime is 2025132019. The next prime is 2025132061. The reversal of 2025132051 is 1502315202.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2025132051 - 25 = 2025132019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2025132001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337522006 + ... + 337522011.

It is an arithmetic number, because the mean of its divisors is an integer number (675044018).

Almost surely, 22025132051 is an apocalyptic number.

2025132051 is a deficient number, since it is larger than the sum of its proper divisors (675044021).

2025132051 is an equidigital number, since it uses as much as digits as its factorization.

2025132051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 675044020.

The product of its (nonzero) digits is 600, while the sum is 21.

The square root of 2025132051 is about 45001.4672094144. The cubic root of 2025132051 is about 1265.1764976331.

Adding to 2025132051 its reverse (1502315202), we get a palindrome (3527447253).

The spelling of 2025132051 in words is "two billion, twenty-five million, one hundred thirty-two thousand, fifty-one".

Divisors: 1 3 675044017 2025132051