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2025142401041 is a prime number
BaseRepresentation
bin11101011110000011111…
…001001011100000010001
321011121020122201011021122
4131132003321023200101
5231134442423313131
64150200525532025
7266211626246564
oct35360371134021
97147218634248
102025142401041
117109490a9921
122885a0114015
13118c7c438a56
1470035b044db
1537a2a42cd7b
hex1d783e4b811

2025142401041 has 2 divisors, whose sum is σ = 2025142401042. Its totient is φ = 2025142401040.

The previous prime is 2025142401019. The next prime is 2025142401043. The reversal of 2025142401041 is 1401042415202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1103926361041 + 921216040000 = 1050679^2 + 959800^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2025142401041 is a prime.

Together with 2025142401043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2025142401041.

It is not a weakly prime, because it can be changed into another prime (2025142401043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012571200520 + 1012571200521.

It is an arithmetic number, because the mean of its divisors is an integer number (1012571200521).

Almost surely, 22025142401041 is an apocalyptic number.

It is an amenable number.

2025142401041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2025142401041 is an equidigital number, since it uses as much as digits as its factorization.

2025142401041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 2025142401041 its reverse (1401042415202), we get a palindrome (3426184816243).

The spelling of 2025142401041 in words is "two trillion, twenty-five billion, one hundred forty-two million, four hundred one thousand, forty-one".