Base | Representation |
---|---|
bin | 10010110111001000… |
… | …111001011010010001 |
3 | 1221021102112010212201 |
4 | 102313020321122101 |
5 | 312434110311032 |
6 | 13145343523201 |
7 | 1314605555206 |
oct | 226710713221 |
9 | 57242463781 |
10 | 20252432017 |
11 | 8652a73a24 |
12 | 3b125b9501 |
13 | 1ba9a8c2ac |
14 | da1a35cad |
15 | 7d7ed08e7 |
hex | 4b7239691 |
20252432017 has 2 divisors, whose sum is σ = 20252432018. Its totient is φ = 20252432016.
The previous prime is 20252432003. The next prime is 20252432047. The reversal of 20252432017 is 71023425202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12087683136 + 8164748881 = 109944^2 + 90359^2 .
It is a cyclic number.
It is not a de Polignac number, because 20252432017 - 223 = 20244043409 is a prime.
It is a super-2 number, since 2×202524320172 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20252432047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10126216008 + 10126216009.
It is an arithmetic number, because the mean of its divisors is an integer number (10126216009).
Almost surely, 220252432017 is an apocalyptic number.
It is an amenable number.
20252432017 is a deficient number, since it is larger than the sum of its proper divisors (1).
20252432017 is an equidigital number, since it uses as much as digits as its factorization.
20252432017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 28.
Adding to 20252432017 its reverse (71023425202), we get a palindrome (91275857219).
The spelling of 20252432017 in words is "twenty billion, two hundred fifty-two million, four hundred thirty-two thousand, seventeen".
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