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20252544205513 is a prime number
BaseRepresentation
bin1001001101011011010011…
…01101000000001011001001
32122201010100121221101121211
410212231221231000023021
510123304202304034023
6111023520152533121
74160124632242264
oct446555155001311
978633317841554
1020252544205513
1164a9068248574
1223310b40b11a1
13b3ba644abb79
1450032a909cdb
15251c3620da0d
hex126b69b402c9

20252544205513 has 2 divisors, whose sum is σ = 20252544205514. Its totient is φ = 20252544205512.

The previous prime is 20252544205511. The next prime is 20252544205603. The reversal of 20252544205513 is 31550244525202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11578830061824 + 8673714143689 = 3402768^2 + 2945117^2 .

It is a cyclic number.

It is not a de Polignac number, because 20252544205513 - 21 = 20252544205511 is a prime.

It is a super-3 number, since 3×202525442055133 (a number of 41 digits) contains 333 as substring.

Together with 20252544205511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (20252544205511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10126272102756 + 10126272102757.

It is an arithmetic number, because the mean of its divisors is an integer number (10126272102757).

Almost surely, 220252544205513 is an apocalyptic number.

It is an amenable number.

20252544205513 is a deficient number, since it is larger than the sum of its proper divisors (1).

20252544205513 is an equidigital number, since it uses as much as digits as its factorization.

20252544205513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480000, while the sum is 40.

The spelling of 20252544205513 in words is "twenty trillion, two hundred fifty-two billion, five hundred forty-four million, two hundred five thousand, five hundred thirteen".