2025435400213 has 2 divisors, whose sum is σ = 2025435400214. Its totient is φ = 2025435400212.

The previous prime is 2025435400187. The next prime is 2025435400231. The reversal of 2025435400213 is 3120045345202.

Together with next prime (2025435400231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1144433527524 + 881001872689 = 1069782^2 + 938617^2 .

It is a cyclic number.

It is not a de Polignac number, because 2025435400213 - 2¹⁷ = 2025435269141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2025435400243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012717700106 + 1012717700107.

It is an arithmetic number, because the mean of its divisors is an integer number (1012717700107).

Almost surely, 2^{2025435400213} is an apocalyptic number.

It is an amenable number.

2025435400213 is a deficient number, since it is larger than the sum of its proper divisors (1).

2025435400213 is an equidigital number, since it uses as much as digits as its factorization.

2025435400213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 31.

The spelling of 2025435400213 in words is "two trillion, twenty-five billion, four hundred thirty-five million, four hundred thousand, two hundred thirteen".