Base | Representation |
---|---|
bin | 11101011110011010000… |
… | …100010111101110011011 |
3 | 21011122012120202100210012 |
4 | 131132122010113232123 |
5 | 231141223143332220 |
6 | 4150301455512135 |
7 | 266224064416253 |
oct | 35363204275633 |
9 | 7148176670705 |
10 | 2025514433435 |
11 | 71101a102309 |
12 | 28868482864b |
13 | 11900b53746c |
14 | 7006d2a8963 |
15 | 37a4ce19ac5 |
hex | 1d79a117b9b |
2025514433435 has 4 divisors (see below), whose sum is σ = 2430617320128. Its totient is φ = 1620411546744.
The previous prime is 2025514433417. The next prime is 2025514433461. The reversal of 2025514433435 is 5343344155202.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2025514433435 - 222 = 2025510239131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2025514433392 and 2025514433401.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202551443339 + ... + 202551443348.
It is an arithmetic number, because the mean of its divisors is an integer number (607654330032).
Almost surely, 22025514433435 is an apocalyptic number.
2025514433435 is a deficient number, since it is larger than the sum of its proper divisors (405102886693).
2025514433435 is an equidigital number, since it uses as much as digits as its factorization.
2025514433435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 405102886692.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 2025514433435 its reverse (5343344155202), we get a palindrome (7368858588637).
The spelling of 2025514433435 in words is "two trillion, twenty-five billion, five hundred fourteen million, four hundred thirty-three thousand, four hundred thirty-five".
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