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20255311345 = 54051062269
BaseRepresentation
bin10010110111010011…
…111000010111110001
31221021121221102120111
4102313103320113301
5312440324430340
613145525341321
71314642206563
oct226723702761
957247842514
1020255311345
118654660235
123b13567841
131baa559a39
14da2185333
157d839daea
hex4b74f85f1

20255311345 has 4 divisors (see below), whose sum is σ = 24306373620. Its totient is φ = 16204249072.

The previous prime is 20255311333. The next prime is 20255311357. The reversal of 20255311345 is 54311355202.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (20255311333) and next prime (20255311357).

It can be written as a sum of positive squares in 2 ways, for example, as 15593016384 + 4662294961 = 124872^2 + 68281^2 .

It is a cyclic number.

It is not a de Polignac number, because 20255311345 - 25 = 20255311313 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2025531130 + ... + 2025531139.

It is an arithmetic number, because the mean of its divisors is an integer number (6076593405).

Almost surely, 220255311345 is an apocalyptic number.

It is an amenable number.

20255311345 is a deficient number, since it is larger than the sum of its proper divisors (4051062275).

20255311345 is an equidigital number, since it uses as much as digits as its factorization.

20255311345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4051062274.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 20255311345 its reverse (54311355202), we get a palindrome (74566666547).

The spelling of 20255311345 in words is "twenty billion, two hundred fifty-five million, three hundred eleven thousand, three hundred forty-five".

Divisors: 1 5 4051062269 20255311345