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20300442013 = 197103047929
BaseRepresentation
bin10010111010000000…
…000010100110011101
31221101202212022012201
4102322000002212131
5313033403121023
613154220531501
71316030624065
oct227200024635
957352768181
1020300442013
118678085605
123b266b0b91
131bb69cb987
14da81723a5
157dc315bad
hex4ba00299d

20300442013 has 4 divisors (see below), whose sum is σ = 20403490140. Its totient is φ = 20197393888.

The previous prime is 20300441981. The next prime is 20300442017. The reversal of 20300442013 is 31024400302.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9852944644 + 10447497369 = 99262^2 + 102213^2 .

It is a cyclic number.

It is not a de Polignac number, because 20300442013 - 25 = 20300441981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20300442017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51523768 + ... + 51524161.

It is an arithmetic number, because the mean of its divisors is an integer number (5100872535).

Almost surely, 220300442013 is an apocalyptic number.

It is an amenable number.

20300442013 is a deficient number, since it is larger than the sum of its proper divisors (103048127).

20300442013 is a wasteful number, since it uses less digits than its factorization.

20300442013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103048126.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 20300442013 its reverse (31024400302), we get a palindrome (51324842315).

The spelling of 20300442013 in words is "twenty billion, three hundred million, four hundred forty-two thousand, thirteen".

Divisors: 1 197 103047929 20300442013