Base | Representation |
---|---|
bin | 10010111010000010… |
… | …101101010100100011 |
3 | 1221101211011211102121 |
4 | 102322002231110203 |
5 | 313034043010113 |
6 | 13154243525111 |
7 | 1316036565553 |
oct | 227202552443 |
9 | 57354154377 |
10 | 20301141283 |
11 | 8678512a15 |
12 | 3b26989797 |
13 | 1bb6bb5047 |
14 | da82b5163 |
15 | 7dc402e8d |
hex | 4ba0ad523 |
20301141283 has 2 divisors, whose sum is σ = 20301141284. Its totient is φ = 20301141282.
The previous prime is 20301141197. The next prime is 20301141293. The reversal of 20301141283 is 38214110302.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20301141283 - 217 = 20301010211 is a prime.
It is not a weakly prime, because it can be changed into another prime (20301141293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10150570641 + 10150570642.
It is an arithmetic number, because the mean of its divisors is an integer number (10150570642).
Almost surely, 220301141283 is an apocalyptic number.
20301141283 is a deficient number, since it is larger than the sum of its proper divisors (1).
20301141283 is an equidigital number, since it uses as much as digits as its factorization.
20301141283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 20301141283 its reverse (38214110302), we get a palindrome (58515251585).
The spelling of 20301141283 in words is "twenty billion, three hundred one million, one hundred forty-one thousand, two hundred eighty-three".
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