Base | Representation |
---|---|
bin | 11101100010101110011… |
… | …001111010011000001101 |
3 | 21012002011200111121202011 |
4 | 131202232121322120031 |
5 | 231230222022421023 |
6 | 4152345512501221 |
7 | 266450011210465 |
oct | 35425631723015 |
9 | 7162150447664 |
10 | 2030150592013 |
11 | 712a890a0925 |
12 | 2895593aa811 |
13 | 119599ba496b |
14 | 7038ccd8ba5 |
15 | 37c1ee5150d |
hex | 1d8ae67a60d |
2030150592013 has 2 divisors, whose sum is σ = 2030150592014. Its totient is φ = 2030150592012.
The previous prime is 2030150592007. The next prime is 2030150592049. The reversal of 2030150592013 is 3102950510302.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1977685315204 + 52465276809 = 1406302^2 + 229053^2 .
It is a cyclic number.
It is not a de Polignac number, because 2030150592013 - 29 = 2030150591501 is a prime.
It is a super-2 number, since 2×20301505920132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2030150592073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015075296006 + 1015075296007.
It is an arithmetic number, because the mean of its divisors is an integer number (1015075296007).
Almost surely, 22030150592013 is an apocalyptic number.
It is an amenable number.
2030150592013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2030150592013 is an equidigital number, since it uses as much as digits as its factorization.
2030150592013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 31.
The spelling of 2030150592013 in words is "two trillion, thirty billion, one hundred fifty million, five hundred ninety-two thousand, thirteen".
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