Base | Representation |
---|---|
bin | 1011110100010100011… |
… | …1110000110000110011 |
3 | 201102001000211101010120 |
4 | 2331011013300300303 |
5 | 11311242410004210 |
6 | 233133442101323 |
7 | 20445050044065 |
oct | 2750507606063 |
9 | 642030741116 |
10 | 203023125555 |
11 | 79113297178 |
12 | 3342004a843 |
13 | 161b673c673 |
14 | 9b7d7c7735 |
15 | 5433a85270 |
hex | 2f451f0c33 |
203023125555 has 8 divisors (see below), whose sum is σ = 324837000912. Its totient is φ = 108279000288.
The previous prime is 203023125553. The next prime is 203023125563. The reversal of 203023125555 is 555521320302.
203023125555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 203023125555 - 21 = 203023125553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (203023125551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6767437504 + ... + 6767437533.
It is an arithmetic number, because the mean of its divisors is an integer number (40604625114).
Almost surely, 2203023125555 is an apocalyptic number.
203023125555 is a deficient number, since it is larger than the sum of its proper divisors (121813875357).
203023125555 is a wasteful number, since it uses less digits than its factorization.
203023125555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13534875045.
The product of its (nonzero) digits is 45000, while the sum is 33.
Adding to 203023125555 its reverse (555521320302), we get a palindrome (758544445857).
The spelling of 203023125555 in words is "two hundred three billion, twenty-three million, one hundred twenty-five thousand, five hundred fifty-five".
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