Base | Representation |
---|---|
bin | 1011110100011000101… |
… | …0010000000001110101 |
3 | 201102002020121220000012 |
4 | 2331012022100001311 |
5 | 11311311340231000 |
6 | 233135303430005 |
7 | 20445351146132 |
oct | 2750612200165 |
9 | 642066556005 |
10 | 203040555125 |
11 | 79122111281 |
12 | 33425a55305 |
13 | 161ba232b15 |
14 | 9b81c43589 |
15 | 5435379735 |
hex | 2f46290075 |
203040555125 has 32 divisors (see below), whose sum is σ = 259417192320. Its totient is φ = 158575603200.
The previous prime is 203040555121. The next prime is 203040555169. The reversal of 203040555125 is 521555040302.
It is not a de Polignac number, because 203040555125 - 22 = 203040555121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 203040555091 and 203040555100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (203040555121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12209066 + ... + 12225684.
It is an arithmetic number, because the mean of its divisors is an integer number (8106787260).
Almost surely, 2203040555125 is an apocalyptic number.
203040555125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
203040555125 is a deficient number, since it is larger than the sum of its proper divisors (56376637195).
203040555125 is a wasteful number, since it uses less digits than its factorization.
203040555125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18950 (or 18940 counting only the distinct ones).
The product of its (nonzero) digits is 30000, while the sum is 32.
Adding to 203040555125 its reverse (521555040302), we get a palindrome (724595595427).
The spelling of 203040555125 in words is "two hundred three billion, forty million, five hundred fifty-five thousand, one hundred twenty-five".
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