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203041510343339 is a prime number
BaseRepresentation
bin101110001010101001001001…
…000110010100001010101011
3222121220120121221221021002012
4232022221021012110022223
5203103113003121441324
61555455552051430135
760524156622550013
oct5612511106241253
9877816557837065
10203041510343339
115977146a3423a8
121a93297abb534b
13893a969a45505
14381d393920c43
151871897ba920e
hexb8aa491942ab

203041510343339 has 2 divisors, whose sum is σ = 203041510343340. Its totient is φ = 203041510343338.

The previous prime is 203041510343333. The next prime is 203041510343341. The reversal of 203041510343339 is 933343015140302.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 203041510343339 - 216 = 203041510277803 is a prime.

Together with 203041510343341, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 203041510343296 and 203041510343305.

It is not a weakly prime, because it can be changed into another prime (203041510343333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101520755171669 + 101520755171670.

It is an arithmetic number, because the mean of its divisors is an integer number (101520755171670).

Almost surely, 2203041510343339 is an apocalyptic number.

203041510343339 is a deficient number, since it is larger than the sum of its proper divisors (1).

203041510343339 is an equidigital number, since it uses as much as digits as its factorization.

203041510343339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 349920, while the sum is 41.

The spelling of 203041510343339 in words is "two hundred three trillion, forty-one billion, five hundred ten million, three hundred forty-three thousand, three hundred thirty-nine".