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20305010142151 = 7171311302521659
BaseRepresentation
bin1001001110111101000001…
…11010101010101111000111
32122220010210001212010101021
410213132200322222233013
510130134130044022101
6111103554244012011
74163663036322550
oct447364072525707
978803701763337
1020305010142151
116519340969289
12233b2b6991007
13b439a60b26a7
14502aa6941327
152532a73015a1
hex1277a0eaabc7

20305010142151 has 16 divisors (see below), whose sum is σ = 24758331713280. Its totient is φ = 16255470291840.

The previous prime is 20305010142143. The next prime is 20305010142161. The reversal of 20305010142151 is 15124101050302.

It is a cyclic number.

It is not a de Polignac number, because 20305010142151 - 23 = 20305010142143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20305010142161) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 651245241 + ... + 651276418.

It is an arithmetic number, because the mean of its divisors is an integer number (1547395732080).

Almost surely, 220305010142151 is an apocalyptic number.

20305010142151 is a deficient number, since it is larger than the sum of its proper divisors (4453321571129).

20305010142151 is a wasteful number, since it uses less digits than its factorization.

20305010142151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1302521814.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 20305010142151 its reverse (15124101050302), we get a palindrome (35429111192453).

The spelling of 20305010142151 in words is "twenty trillion, three hundred five billion, ten million, one hundred forty-two thousand, one hundred fifty-one".

Divisors: 1 7 17 119 131 917 2227 15589 1302521659 9117651613 22142868203 155000077421 170630337329 1194412361303 2900715734593 20305010142151