Base | Representation |
---|---|
bin | 11101100011000100101… |
… | …110100011000001011111 |
3 | 21012010010210012121022001 |
4 | 131203010232203001133 |
5 | 231232003411201002 |
6 | 4152451011503131 |
7 | 266462206401046 |
oct | 35430456430137 |
9 | 7163123177261 |
10 | 2030525100127 |
11 | 713160535367 |
12 | 2896428b7aa7 |
13 | 11962965c1b4 |
14 | 703c694555d |
15 | 37c42c7ba87 |
hex | 1d8c4ba305f |
2030525100127 has 4 divisors (see below), whose sum is σ = 2031006385480. Its totient is φ = 2030043814776.
The previous prime is 2030525100077. The next prime is 2030525100239. The reversal of 2030525100127 is 7210015250302.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2030525100127 - 211 = 2030525098079 is a prime.
It is a super-2 number, since 2×20305251001272 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2030525100095 and 2030525100104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2030525100427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240636348 + ... + 240644785.
It is an arithmetic number, because the mean of its divisors is an integer number (507751596370).
Almost surely, 22030525100127 is an apocalyptic number.
2030525100127 is a deficient number, since it is larger than the sum of its proper divisors (481285353).
2030525100127 is an equidigital number, since it uses as much as digits as its factorization.
2030525100127 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 481285352.
The product of its (nonzero) digits is 4200, while the sum is 28.
The spelling of 2030525100127 in words is "two trillion, thirty billion, five hundred twenty-five million, one hundred thousand, one hundred twenty-seven".
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