Base | Representation |
---|---|
bin | 1001001111001000101000… |
… | …10000011111101110001101 |
3 | 2122220201212020211102122121 |
4 | 10213210110100133232031 |
5 | 10130234404443230331 |
6 | 111110504400012541 |
7 | 4164303316122562 |
oct | 447442420375615 |
9 | 78821766742577 |
10 | 20311240211341 |
11 | 6520a4864a4a2 |
12 | 2340555301151 |
13 | b44459a33071 |
14 | 5030d811c869 |
15 | 25351e232c11 |
hex | 12791441fb8d |
20311240211341 has 2 divisors, whose sum is σ = 20311240211342. Its totient is φ = 20311240211340.
The previous prime is 20311240211333. The next prime is 20311240211347. The reversal of 20311240211341 is 14311204211302.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20311156104100 + 84107241 = 4506790^2 + 9171^2 .
It is a cyclic number.
It is not a de Polignac number, because 20311240211341 - 23 = 20311240211333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20311240211347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10155620105670 + 10155620105671.
It is an arithmetic number, because the mean of its divisors is an integer number (10155620105671).
Almost surely, 220311240211341 is an apocalyptic number.
It is an amenable number.
20311240211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
20311240211341 is an equidigital number, since it uses as much as digits as its factorization.
20311240211341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 20311240211341 its reverse (14311204211302), we get a palindrome (34622444422643).
The spelling of 20311240211341 in words is "twenty trillion, three hundred eleven billion, two hundred forty million, two hundred eleven thousand, three hundred forty-one".
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