Search a number
-
+
203121400433981 is a prime number
BaseRepresentation
bin101110001011110011100010…
…111010110100110100111101
3222122012012211122020100210012
4232023303202322310310331
5203110420112002341411
62000000403321353005
760533015441245121
oct5613634272646475
9878165748210705
10203121400433981
11597a23361a99a7
121a946356038765
13894535c1772b3
1438231b1c49581
1518739c16b718b
hexb8bce2eb4d3d

203121400433981 has 2 divisors, whose sum is σ = 203121400433982. Its totient is φ = 203121400433980.

The previous prime is 203121400433971. The next prime is 203121400434061. The reversal of 203121400433981 is 189334004121302.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 196883244817081 + 6238155616900 = 14031509^2 + 2497630^2 .

It is a cyclic number.

It is not a de Polignac number, because 203121400433981 - 214 = 203121400417597 is a prime.

It is a super-3 number, since 3×2031214004339813 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (203121400433971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101560700216990 + 101560700216991.

It is an arithmetic number, because the mean of its divisors is an integer number (101560700216991).

Almost surely, 2203121400433981 is an apocalyptic number.

It is an amenable number.

203121400433981 is a deficient number, since it is larger than the sum of its proper divisors (1).

203121400433981 is an equidigital number, since it uses as much as digits as its factorization.

203121400433981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 203121400433981 in words is "two hundred three trillion, one hundred twenty-one billion, four hundred million, four hundred thirty-three thousand, nine hundred eighty-one".